46 lines
1.8 KiB
Python
46 lines
1.8 KiB
Python
#
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# Copyright (c) 2022 Pim van Pelt
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#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at:
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# http://www.apache.org/licenses/LICENSE-2.0
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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#
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import logging
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def get_lcps(yaml, interfaces=True, loopbacks=True, bridgedomains=True):
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""" Returns a list of LCPs configured in the system. Optionally (de)select the different
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types of LCP. Return an empty list if there are none of the given type(s). """
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ret = []
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if interfaces and 'interfaces' in yaml:
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for ifname, iface in yaml['interfaces'].items():
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if 'lcp' in iface:
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ret.append(iface['lcp'])
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if 'sub-interfaces' in iface:
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for subid, sub_iface in iface['sub-interfaces'].items():
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if 'lcp' in sub_iface:
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ret.append(sub_iface['lcp'])
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if loopbacks and 'loopbacks' in yaml:
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for ifname, iface in yaml['loopbacks'].items():
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if 'lcp' in iface:
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ret.append(iface['lcp'])
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if bridgedomains and 'bridgedomains' in yaml:
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for ifname, iface in yaml['bridgedomains'].items():
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if 'lcp' in iface:
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ret.append(iface['lcp'])
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return ret
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def is_unique(yaml, lcpname):
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""" Returns True if there is at most one occurence of the LCP name in the entire config."""
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lcps = get_lcps(yaml)
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return lcps.count(lcpname) < 2
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