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Move to explicit 'plan -o XXX' commandline

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This commit is contained in:
Pim van Pelt
2022-04-03 11:20:47 +00:00
parent b67493003f
commit 1a0daa48d1
1 changed files with 4 additions and 4 deletions
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8
intest/intest.sh
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@ -11,19 +11,19 @@
for i in hippo[0-9]*.yaml; do
echo "Clearing: Moving to hippo-empty.yaml"
../vppcfg -s ../schema.yaml -c hippo-empty.yaml > /tmp/vppcfg-exec-empty
../vppcfg -s ../schema.yaml -c hippo-empty.yaml plan -o /tmp/vppcfg-exec-empty
[ -s /tmp/vppcfg-exec-empty ] && vppctl exec /tmp/vppcfg-exec-empty
for j in hippo[0-9]*.yaml; do
echo " - Moving to $i .. "
../vppcfg -s ../schema.yaml -c $i > /tmp/vppcfg-exec_$i
../vppcfg -s ../schema.yaml -c $i plan -o /tmp/vppcfg-exec_$i
[ -s /tmp/vppcfg-exec_$i ] && vppctl exec /tmp/vppcfg-exec_$i
echo " - Moving from $i to $j"
../vppcfg -s ../schema.yaml -c $j > /tmp/vppcfg-exec_${i}_${j}
../vppcfg -s ../schema.yaml -c $j plan -o /tmp/vppcfg-exec_${i}_${j}
[ -s /tmp/vppcfg-exec_${i}_${j} ] && vppctl exec /tmp/vppcfg-exec_${i}_${j}
echo " - Checking that from $j to $j is empty"
../vppcfg -s ../schema.yaml -c $j > /tmp/vppcfg-exec_${j}_${j}_null
../vppcfg -s ../schema.yaml -c $j plan -o /tmp/vppcfg-exec_${j}_${j}_null
done
done